Tuesday, December 29, 2009

Round Extending Table If There Is A Circle And 30 Knights Around It, (equally Spaced) Radius Of 12, And Spear L Of 10 Howmanytaps?

If there is a circle and 30 knights around it, (equally spaced) radius of 12, and spear L of 10 howmanytaps? - round extending table

Help me pls! I apprectaite! I've been blocked for 3 hours ... I need help from someone who can understand the problem. I think it has something to do with bows and strings. Here the problem is with more details:

Imagine 30 knights at a round table, spaced
also on the board. Each horse can extend his spear
for up to 10 meters from his sitting position. (For this you need
arm's length into account.) Table has a radius of
12 feet.
King Arthur enters the room and lift the cup.
Standing by the table, drink in honor of his knights.
In response, the men from every faucet Spears with all other
Men who are very close. As the spear is
there?

1 comment:

  1. Nice question. So basically, if it could be 2 knight everywhere are on the table, is what the maximum distance) (on the extent to which you can still play the spears.

    Look at it this way. If you spear me in touch with another man, and our spears are directly at an angle to the other (s) on the table, it could actually also sit as the Lords of the maximum distance, if they "stretch their hoses directly to the other.

    So, what angle of a rope 20 meters in a circle with a radius of 12 feet? A little trigonometry shows 10/12 = sin (theta / 2), where theta is the angle between the chord in a circle, if they form a triangle of rope and 2 radios. Then theta = 1.97 rad.

    The distance between each horse 2pi/30 = 0.20944 rad. Therefore, we find that when more than 8 knight between me and another (then on both sides of me the whole circle ...) I can not touch him with spears.

    Each horse can reach lance with 18 other people. The rest is now combinatorics. MaABB someone else can add, I'm too tired to think of it!

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